黑雨

import javax.swing.JOptionPane;
public class Eg26
{
public static void main(String[] args)
{

int he = 0;
int Bai = 0;
int Shi = 0;
int Ge = 0;
int Zheng = 0;
while(Zheng <= 0 || Zheng >= 1000)
{
String zheng = JOptionPane.showInputDialog(null,"Enter a int value",
"Example 2.1 Input (double)",JOptionPane.QUESTION_MESSAGE);
Zheng = Integer.parseInt(zheng);
}

Ge = Zheng % 10;
Shi = (Zheng / 10) % 10;
Bai = Zheng / 100;
he = Ge + Shi + Bai;
JOptionPane.showMessageDialog(null,he,
"Example 2.1 Output(double)",JOptionPane.INFORMATION_MESSAGE);


}


}
如何对输入的字符或符号进行限制
如果输入值不为1到1000之间的数将重新输入

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状态 离线  #2发表于 2007-10-16 02:29  资料  个人空间  短消息  加为好友   
add one while loop construction, check "Zheng" value, if it doesn't below 0 -1000 ,then going into the loop, repeat askinig input value.

import javax.swing.JOptionPane;
class Eg26
{
public static void main(String[] args)
{

int he = 0;
int Bai = 0;
int Shi = 0;
int Ge = 0;
int Zheng = 0;
while(Zheng <= 0 || Zheng >= 1000)
{
String zheng = JOptionPane.showInputDialog(null,"Enter a int value",
"Example 2.1 Input (double)",JOptionPane.QUESTION_MESSAGE);

Zheng = Integer.parseInt(zheng);

while (Zheng > 1000 || Zheng < 0)
{
zheng = JOptionPane.showInputDialog(null,"You Must entry (0 - 1000),try again!",
"Example 2.1 Input (double)",JOptionPane.QUESTION_MESSAGE);

Zheng = Integer.parseInt(zheng);        
}

}

Ge = Zheng % 10;
Shi = (Zheng / 10) % 10;
Bai = Zheng / 100;
he = Ge + Shi + Bai;
JOptionPane.showMessageDialog(null,he,
"Example 2.1 Output(double)",JOptionPane.INFORMATION_MESSAGE);


}


}